Problem:

"The eqation of motion is given for a particle, where s is inmeters and t is in seconds. Find the acceleration after 4.5seconds"

s=sin(2*pi*t)

This is what I am doing.

a(t) = v'(t) = s"(t)

s'(t) = 2*pi*cos(2*pi*t)

s"(t) = -4*pi^2*sin(2* pi*t)

where I now get s"(t)= -18.70067946.

I am told this is the incorrect answer, although being away fromcampus for a few days I've not been able to get any help on this,any thoughts as what I am doing incorrect?

"The eqation of motion is given for a particle, where s is inmeters and t is in seconds. Find the acceleration after 4.5seconds"

s=sin(2*pi*t)

This is what I am doing.

a(t) = v'(t) = s"(t)

s'(t) = 2*pi*cos(2*pi*t)

s"(t) = -4*pi^2*sin(2* pi*t)

where I now get s"(t)= -18.70067946.

I am told this is the incorrect answer, although being away fromcampus for a few days I've not been able to get any help on this,any thoughts as what I am doing incorrect?

## Answers ( 2 )

s'(t) = 2*pi*cos(2*pi*t)

s"(t) = -4*pi^2*sin(2* pi*t)

Now it is given that t=4.5 s. Try converitn it into degrees bymultiplying with 180 and dividing with pi