Problem: "The eqation of motion is given for a par...

Problem:
"The eqation of motion is given for a particle, where s is inmeters and t is in seconds. Find the acceleration after 4.5seconds"
s=sin(2*pi*t)

This is what I am doing.

a(t) = v'(t) = s"(t)

s'(t) = 2*pi*cos(2*pi*t)

s"(t) = -4*pi^2*sin(2* pi*t)

where I now get s"(t)= -18.70067946.
I am told this is the incorrect answer, although being away fromcampus for a few days I've not been able to get any help on this,any thoughts as what I am doing incorrect?

Answers ( 2 )

  1. scarlett owens
    scarlett owens
    a(t) = v'(t) = s"(t)

    s'(t) = 2*pi*cos(2*pi*t)

    s"(t) = -4*pi^2*sin(2* pi*t)
    Now it is given that t=4.5 s. Try converitn it into degrees bymultiplying with 180 and dividing with pi
    this gives s''(4.5) = -4*pi^2sin 2*pi*4.5*180/pi) =-4pi^2sin(9*180)= 0
    I dont know weather it is correct.
    Any body else, please help
  2. liam thompson
    liam thompson
    the answer must be 0.
    s'' = -4 = 0

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