# Obtain a polynomial f such that where i = 2 to n...

Obtain a polynomial f such that

where i = 2 to n

I know that

sum, from i=2 to i=n, of x

^{i}is the same as [(sum,from i=0 to i=n, of x^{i})-x^{0}-x^{1}].Getting stuck to use it

## Answers ( 4 )

^{i}= sum(x^{i})^{i+1}) -sum(x^{i}), and sum(x^{i+1}) = sum(x^{i}) +x^{n+1}- x^{2}^{i}) + x^{n+1}- x^{2}-sum(x^{i})^{n+1}- x^{2}^{i})*(x-1) = (x^{2}+x^{3})(x-1) = x(x^{2}+ x^{3}) -(x^{2}+ x^{3})(1) = (x^{2+1}+x^{3+1}) - (x^{2}+ x^{3})... etc... getit? :)how did you get to

^{i+1}) -sum(x^{i}), and sum(x^{i+1}) = sum(x^{i}) +x^{n+1}- x^{2}