Given x^2 + 2y^2 =3 find the tangent and normal li...

given
x^2 + 2y^2 =3
find the tangent and normal lines at (1,1)
so I think that I find y' first
2x + 4yy' = 0
and
y' = (3-2x)/4y
setting this to 0 to get the tangent line slope gives
3-2x=0 and x = 3/2
I think this is so far correct, but I am not sure what isnext.
thanks

Answers ( 1 )

  1. julian suarez
    julian suarez
    Yes there is ofcourse a correction.
    y ' = -2x/4y = -x/2y [noty' = (3-2x)/4y]
    This gives you m = -1/2
    Please make the changes and get the answer.

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