8.[HRW7 9.P.060.] Asteel ball of mass 0.600 kg isf...

8.[HRW7 9.P.060.] Asteel ball of mass 0.600 kg isfastened to a cord that is 50.0 cmlong and fixed at the far end. The ball is then released when thecord is horizontal (Figure 9-65). At the bottom of its path, theball strikes a 3.00 kg steel blockinitially at rest on a frictionless surface. The collision iselastic.


Fig. 9-65

(a) Find the speed of the ball just aftercollision.
m/s
(b) Find the speed of the block just after collision.
m/s

Answers ( 1 )

  1. viktor sauer
    viktor sauer
    Mass of ball = m1
    Mass of block = m2
    Initial Velocity of ball = v1
                                           v1    = ( 2gh ) 1/2 = 3.13m/s
    Final velocity of ball after collision = v1'
    Velocity of block after collision = v2'
    Using conservation of momentum for the elastic collision wehave
                     v1' = v1 ( m1 - m2) /( ( m1 + m2)
                      v1' =- 2.09m/s ( reverse direction )

    b) speed of the block v2 ' =2m1v1/ ( m1 +m2)
                                      v2' = 1.04 m/s (forward direction )


                            

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