A 118 g cube of ice at 0°C isdropped into 1.0 kg ...

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  1. julian suarez
    julian suarez


    Let the final temperature of water be = t'C
    Using he principle of calori metry, we have
    Heat lost by water at 84'C = Heat gained by ice to melt it towater + Rise the temperature of melted water from 0'C to waterat t'C
                  mw Cw ( 84 - t ) = miLi + mi Cw( t - 0 )
                      84  mwCw - mw Cw t = miLi + mi Cw t
                                 t Cw (  mi  +mw ) = 84  mw Cw - mi Li
       Here mass of ice mi  =0.118kg   
               mass of water mw =1.0kg
               latent heat of iceLi =3.33*105   J/kg
               specific heat of waterCw =4186J/kg'C  
    Substituting the values the final temperature of water iscalculated.
                                        t = 65'C


                      

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